LINEAR GRAPH : y = ax^0 or y = ax^1
========================================================================
Case 1: when n =0
y= 2x^0
y=-2x^0
The points are all linear which has a constant gradient.
The gradient is dependent on the value of a. if a >0 then gradient is positive, if a < 0 then the gradient is negative. However if a =0 gradient is zero.
Absence of turning point and line of symmetry
The y intercept is dependent on what the value of c is.
Case 2:when n=1
y= 3/4x^1+4
y=3/4x^1
y=-3/4x^1
y=-3/4x^1-4
The line is also linear.
The gradient is dependent on the value of a. if a >0 then gradient is positive, if a < 0 then the gradient is negative. However if a =0 gradient is zero.
The y intercept is dependent on b in the y=ax+b equation.
Proudly brought to you
No comments:
Post a Comment